there are 1300 people surveyed on job satisfaction: 750 men %26amp; 550 women
Suppose that one of the 1300 employees surveyed is chosen at random:
1. What is the probability that he or she feels that a good relationship with the boss is extremely important?
2. What is the probability that the employee is a female who feels that a good relationship with the boss is extremely important?
3. Given that the chosen employee considers that having a good relationship with the boss is extremely important, what is the probability that this employee is a female?
Here is the data needed:
Good Relationship with Boss: Men:61% Women: 77%
thank you very much
Probability questions?
M = Male
F = Female
G = Good relationship with boss.
P(M) = 750/1300 (probability that the chosen person is male)
P(F) = 550/1300 (probability that the chosen person is female)
P(G/M)=0.61
P(G/F)=0.77
1) P(G) = P(M) P(G/M)+ P(F) P(G/F)
P(G) = (750/1300) (0.61) + (550/1300)(0.77)
0.3519+0.3258=0.6777
2)P(F)P(G/F)= (550/1300)(0.77)=0.3258
3)P(F/G) = P(F)P(G/F) / [P(F)P(G/F)+P(M)P(G/M)]
= (550/1300)(0.77) / 0.6777
You can simplify this.
Reply:1. You must add the number of satisfied men and women and divide by the total number of applicants, and then multiply by 100%.
61% MALE of 750 = 457.5
77% FEMALE of 550 = 423.5
457.5 + 423.5 = 881
(881/ 1300) x 100% =
ANSWER 67.6%
2. There are 423.5 females who feel a good relationship with the boss is important. You take this number and divide by the total number of applicants, and then multiply by 100% to get your answer.
(423.5 / 1300) x 100% = 32.57%
3. You must divide the number of females who think a relationship with the boss is important (423.5) by the total number of people who feel that way (881), and then multiply by 100%.
(423.5 / 881) x 100% = 48.07%
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